Consider the unbalanced redox equation, VO43-(aq) + SO2(g) + H+(aq) VO2+(aq) + SO42-(aq) + H2O(l) The reducing agent is

Answer 1

S in SO₂ has an oxidation number of +4

S in SO₄^2- has an oxidation number of +6

S has been oxidized and so the reducing agent is SO₂

On the left side of the equation V has an oxidation number of +5

On the right side, V has an oxidation number of +4

V has been reduced so it is the oxidizing agent