Consider the given reaction. A(aq)+B(s)↽−−⇀C(aq)𝐾=9.40 Suppose 15.5 mol A reacts with excess B in 7.80 L of solution. Calculate the concentration of C at equilibrium. [C]= M

Answer 1

A(aq) + B(s) <==> C(aq) ... K = 9.40

K = 9.40 = [C] / [A] (note, solids are not included the equilibrium expression)

15.5 mol A / 7.80 L = 1.99 M

A(aq) + B(s) <==> C(aq)

1.99........................0..........Initial

-x...........................+x.........Change

1.99-x.....................x...........Equilibrium

9.40 = x / 1.99-x

18.7 - 9.40x = x

10.40x = 18.7

x = 0.556 M = [C]

(be sure to check the math)