What is the equilibrium concentration of C if the reaction begins with 0.200 M A and 0.600 M B?

Question

For the reaction below, Kc = 1.10 × 10⁻⁴. \What is the equilibrium concentration of C if the reaction begins with 0.200 M A and 0.600 M B?

 2 A (aq) + B (aq) ⇌ C (aq)

Answer 1

ICE table

2 A (aq) + B (aq) ⇌ C (aq)

0.2………0.6………0……Initial

-2x………-x……….+x…..Change

0.2-2x….0.6-x……..x……Equilibrium

K = [C] / [A]²[B]

1.10x10^-4 = x / (0.2-2x)²(0.6-x)

assume x is small relative to 0.2 and ignore it in the denominator

solve for x and that will be the [C] at equilibrium.