If Kc = 0.0023 for the reaction below at 298.0 K, then what is the value of Kp?

Question

If Kc = 0.0023 for the reaction below at 298.0 K, then what is the value of Kp? (R = 0.0821 L･atm/mol･K.)



3 A (g) + B (g) ⇌ C (g) + D (g)

Answer 1

Kp = Kc(RT)^Δn where Δn is change in moles of gas = 2-4 = -2

Kp = 0.0023 (0821*298)^-2

Solve for Kp