At equilibrium a 2.0L reaction vessel contained a mixture of 1.2 mol fe, 1x10^-3 mol O2 and 2 mol of fe2o3 at 2000°c. What are the values of kc and kp for this reaction

Question

4Fe (s) + 3O2 (g) = 2Fe2O3 (s)

Answer 1

The reaction in question is the following:

4Fe(s) + 3O₂ ==> 2Fe₂O₃(s)

Kc = 1 / [O₂]³

[O₂] = 1x10^-3 mol / 2.0 L = 5x10^-4 M

Kc = 1 / (5x10^-4)³ = 1 / 1.25x10^-10

Kc = 8x10⁹

Kp = Kc(RT)^∆n = (8x10⁹)(0.0821x2273)^-3

Kp = 8x10⁹ x 1.5x10^-7

Kp = 1200

(be sure to check all of the math)