If Kc = 0.0096 for the reaction below at 298.0 K, then what is the value of Kp? (R = 0.0821 L･atm/mol･K.) 3 A (g) + B (g) ⇌ C (g) + D (g)

Question

If Kc = 0.0096 for the reaction below at 298.0 K, then what is the value of Kp? (R = 0.0821 L･atm/mol･K.)   3 A (g) + B (g) ⇌ C (g) + D (g)

J.R. S. · Accepted Answer

Kp = Kc(RT)Δn where Δn is change in moles of gas = 2-6 = -4Kp = 0.0096(.0821*298)-4﻿

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