The value of Kp for the reaction 2 A(g) + B(g) + 3 C(g) → 2 D(g) + E(g) is 14970 at a particular temperature. What would be the value of Kp for the reaction 6 A(g) + 3 B(g) + 9 C(g) →6 D(g) + 3 E(g)?

Answer 1

The second reaction is three times the first. That is, in order to get the second reac you have to multiply the first by 3. This means the value of K for the second reaction is the K of the first reaction cubed. So it is (14970)³