What is the equation of a straight line for this problem: perpendicular to y= -2x/5 + 7, passing through (4, 6)

Answer 1

y = mx + b

The product of slopes of perpendicular lines is -1. The slope of the given line is -2/5, so the slope of the perpendicular line is 5/2.

y = (5/2)x + b

Now use the given point to find b and finish from here.

6 = (5/2)(4) + b

b = -4

equation of a line perpendicular to y is:

y=5x/2-4