J.R. S. answered 03/02/22
Ph.D. University Professor with 10+ years Tutoring Experience
2H2S(g) + CH4(g) -> 4H2(g) + CS2(g)
Kc = [H2]4[CS2] / [H2S]2[CH4]
Kc for 1 mole H2S = sqrt 5.27 * 10-8 = 2.3x10-4
H2((g) + O2(g) + C(graphite) -> HCHO(g) Δ H° f = -108.6 kJ mol-1
Kp = (HCHO) / (H2)(O2)
Since ΔH is negative, this means heat is generated and can be viewed as a product. Increasing reaction temperature will shift the reaction to the left to counteract the change. This is in accord with Le Chatelier.