Mark M. answered 02/28/22
Retired Math prof with teaching and tutoring experience in trig.
cos(3x) = √2/2
3x = π/4 + 2kπ or 7π/4 + 2kπ, where k = 0, 1, -1, 2, -2, ...
So, x = π/12 + 2kπ/3 or 7π/12 + 2kπ/3
Micheal W.
asked 02/28/22I don't even know where to start, please show work:)
Mark M. answered 02/28/22
Retired Math prof with teaching and tutoring experience in trig.
cos(3x) = √2/2
3x = π/4 + 2kπ or 7π/4 + 2kπ, where k = 0, 1, -1, 2, -2, ...
So, x = π/12 + 2kπ/3 or 7π/12 + 2kπ/3
Mark M. answered 02/28/22
Mathematics Teacher - NCLB Highly Qualified
Start by dividing both sides by 3.
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