what is the z value

Question

According to a 2009 Reader's Digest article, people throw away about 11% of what they buy at the grocery store. Assume this is the true proportion and you plan to randomly survey 199 grocery shoppers to investigate their behavior. What is the probability that the sample proportion does not exceed 0.16?

Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach and calculations.

Answer 1

Solution

11% of 199 is 21.89.

So to write it as a fraction it can be written as 21.89/199 = 0.11 which is less than 0.16