1) mean of sampling distributions for proportions = .58
2) standard error = sqrt[p(1-p)/n] = sqrt[.58(1-.58)/135] = .0425
Daniela R.
asked 02/28/22Suppose the true proportion of voters in the county who support a specific candidate is 0.58. Consider the sampling distribution for the proportion of supporters with sample size n = 135.
What is the mean of this distribution?
What is the standard error of this distribution?
1) mean of sampling distributions for proportions = .58
2) standard error = sqrt[p(1-p)/n] = sqrt[.58(1-.58)/135] = .0425
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