If n=15, x-bar=32, and s=6 find the margin of error at a 80% confidence level

Answer 1

margin of error = critical t * s/sqrt(n)

critical t for 80% CI and n = 15, is t-score for tail alpha = 0.1 and 15 - 1 = 14 DOF, which i= 1.345

so margin of error = 1.345 * 6/sqrt(15) = -0.204