How many grams of water can be heated from 20.5oC to 32.8oC by the heat released from 87.3 g of iron that cools from 87.0oC to 28.9oC?

Answer 1

We will need the specific heat for iron, which from an internet source is 0.44 J/gº

The standard specific heat for water is 4.184 J/gº

Heat lost by iron must equal heat gained by water

heat lost by iron = q = mC∆T = (87.3 g)(0.44 J/gº)(58.1º) = 2232 J

heat gained by water = q = mC∆T = (m)(4.184 J/gº)(12.3º) = 51

2232 J = 51 mgJ

m = 43.8 g of water