probability is 0.25 that the student gets each answer correct and 0.75 that they get it wrong. this is a binomial distribution.
x P(x)
0 (0.75)^5= 0.237
1 5 * (0.25) (0.75)^4= 0.396
2 10 * (0.25)^2 (0.75)^3 = 0.264
3 10 * (0.25)^3 * (0.75)^2 = 0.088
4 5 * (0.25)^4 * 0.75 = 0.015
5 (0.25)^5 = 0.001
probability only answer 3 is 0.088
probability at most 3 = 0.237 + 0.396 + 0.264 + 0.088 = 0.985
Hannah W.
Let X = N (μ = 4, σ = 10). A sample of size 25 is randomly selected from this distribution. Find the unknown x such that (1) P[X03/16/22
Hannah W.
thank you so much for your help. Do you by any chance also know this? I have been struggling with this question for so long Let X = N (μ = 4, σ = 10). A sample of size 25 is randomly selected from this distribution. Find the unknown x such that (1) P[X03/16/22