J.R. S. answered 02/25/22
Ph.D. University Professor with 10+ years Tutoring Experience
2H2O(g)↽−−⇀2H2 (g) +O2(g)
0.0100..........0.0025....0.0075 atm
Kp = (H2)2(O2) / (H2O)2
Kp = (0.0025)2(0.0075) / (0.01)2
Kp = 4.69x10-4
Renata A.
asked 02/25/222H2O(g)↽−−⇀2H2(g)+O2(g)
proceeds at a certain temperature until the partial pressures of H2O,H2, and O2 reach 0.0100 atm, 0.00250 atm, and 0.00750 atm, respectively. What is the value of the equilibrium constant at this temperature?
Kp=______
J.R. S. answered 02/25/22
Ph.D. University Professor with 10+ years Tutoring Experience
2H2O(g)↽−−⇀2H2 (g) +O2(g)
0.0100..........0.0025....0.0075 atm
Kp = (H2)2(O2) / (H2O)2
Kp = (0.0025)2(0.0075) / (0.01)2
Kp = 4.69x10-4
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