A photon has a frequency of 2.3 × 10⁸ Hz. What is the energy of this photon?

Answer 1

To find the energy of a photon, you need to use the equation E_photon = (nu)(h)

nu is the frequency

1 Hz = 1 s^-1

2.3 x 10⁸ Hz = 2.3 x 10⁸ s^-1

h is Planck's constant which is 6.626 x 10^-34 J*s

E_photon = (2.3 x 10⁸ s^-1)( 6.626 x 10^-34 J*s)

E_photon = 1.52 x 10^-25 J/photon

Answer 2

E = hν

E = energy = ?

h = Plank's constant = 6.626x10^-34 Jsec

ν = frequency = 2.3x10⁸ Hz = 2.3x10⁸ sec^-1

E = (6.626x10^-34 Jsec)(2.3x10⁸ sec^-1)

E = 1.52x10^-25 J