Determine the energy, in J, of a photon with a wavelength of 311 nm. (h = 6.626 × 10⁻³⁴ J • s and c = 3.00 × 10⁸ m/s)

Answer 1

E = hc/λ

E = energy = ?

h = Plank's constant = 6.626x10^-34 Jsec

c = speed of light = 3.00x10⁸ m/sec

λ = wavelength = 311 nm x 1 m / 10⁹ nm = 3.11x10^-7 m (note: change nm to meters since c is in meters)

E = (6.626x10^-34 Jsec)(3.00x10⁸ m/s) / 3.11x10^-7 m

E = 6.39x10^-19 J