How many millimeters of a 1.30 M NaCl solution are needed to prepare 0.50 L of 0.10 M NaCl?

Answer 1

V1M1 = V2M2

V1 = initial volume = ?

M1 = initial concentration = 1.30 M

V2 = final volume = 0.50 L

M2 = final concentration = 010 M

(x L)(1.30 M) = (0.50 L)(0.10 M)

x = 0.038 L = 38 mls (2 sig. figs.)