Draw the force vector parallelogram with 34.5° being the angle at the attachment of the forces to the ship. The triangle that includes the two force vectors and has a third side that is the resultant vector (the vector sum of the forces) requires the other angle of the parallelogram 1/2 (360-2(34.5)) = 180 - 34.5 = 145.5 = θ
Now you can use cosine law to find the resultant FTot2 = F12 + F22 - F1F2cos(θ)
The problem mentions the equilibrant, which doesn't exist unless the system is in mechanical equilibrium (going a constant speed). In equilibrium the equilibrant is of the same magnitude as the resultant and in the opposite direction.