Peter R. answered 02/24/22
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
D = rt Let's say car #1 is faster than car #2, so r1 = r2 + 5.
They both travel for 5 hrs (t). D1 is r1 x t miles or 5r1 miles, but r1 = r2 + 5, so substitute:
D1 = 5(r2 + 5) miles
D2 is 5r2 miles
D1 + D2 = 550, so 5(r2 + 5) + 5r2 = 550, then 5r2 + 25 + 5r2 = 550
10r2 = 525, so r2 = 52.5 mph and r1 = r2 + 5 = 52.5 + 5 = 57.5 mph
Check: Car #1 57.5 x 5 = 287.5 mi
Car #2 52.5 x 5 = 262.5 mi
Total is 550.0 mi