Find the equation of the location of the second street in standard form.

Question

A contractor is building a new subdivision on the outside of a city. He has started work on the first street and is planning for the other streets to run in a direction parallel to the first. The second street will pass through (−5, −1). Find the equation of the location of the second street in standard form.

x − y = −6

2x + y = −11

x + y = −6

2x − y = −9

Answer 1

street 1 is y =-x +1

street 2 is y =-x +b, solve for b by plugging in (-5,-1)

-1 =-(-5) +b

b= -1-5 = -6

y=-x -6 in slope intercept form

in standard form

x+y = -6