What is the frequency in Hertz of a photon emitted after an electron transitions from n=6 to n=2?

Question

(Hint: You first need to find the energy and then the frequency) (show your calculations)

Answer 1

To find the energy of the electron use this formula:

∆E = R_H (1/n_f² - 1/n_i²⁾

RH = -2.179x10^-18 J

n_f= final energy level = 2

n_i = initial energy level = 6

∆E = -2.179x10^-18 J (0.250 - 0.0278)

∆E = -2.179x10^-18 J (0.222)

∆E = -4.84x10^-19 J (the negative sign is because energy is emitted/given off)

To find the frequency (ν), use the following formula:

ν = E/h

E = 4.84x10^-19 J

h = Plank's constant = 6.626x10^-34 Jsec

ν = 4.84x10^-19 J / 6.626x10^-34 Jsec

ν = 7.30x10¹⁴sec^-1 = 7.30x10¹⁴ Hz