Balanced equations

Question

For the balanced equation shown below, how many grams of KClO3 reacted, if 9.52 grams of KCl are produced? 2KClO3 → 2KCl+3O2

Answer 1

2KClO₃ → 2KCl + 3O₂ ... balanced equation

molar mass KClO₃= 122.5 g/mol

molar mass KCl = 74.55 g/mol

mols KCl produced = 9.52 g x 1 mol KCl / 74.55 g = 0.1277 mols

mols KClO₃ neeeded = 0.1227 mols KCl x 2 mols KClO₃ / 2 mol KCl = 0.1277 mols KClO₃ needed

grams KClO₃ needed = 0.1277 mols KClO₃ x 122.5 g/mol = 15.6 g KClO₃ (3 sig. figs.)