
MUHAMMAD I. answered 02/15/22
i'm proficient in coaching arithmetic,from fundamental to college
Decision variables: the number of machines available and the demand for tyres. Decision variables are Xij, with i representing the number of machines bought t a specific quarter and the number of quarters that the machine has been used. Constraints; the number of machines, their production capacities, and the number of quarters each machine should be used. Objective function; minimize inventory costs and maximize production of tyres. Maximizing profit is the objective function +
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Decision variables:
The decision variables are Xij, where i represents the number of machines bought in quarter i (at least 2 quarters) and j represents the number of machines for the remaining two quarters.
Objective function:
We need to specify a criterion for evaluation—an objective function. The most appropriate objective function is to maximize monthly profit. The profit earned is a direct function of the amount of each machine i.e. the decision variables. Monthly profit, designated as z, is written as follows:
z (profit per tyre) * (number of tyres made and sold monthly).
Constraints:
We want to maximize z, but subject to satisfying the stated constraints. To solve the problem, we express these constraints as mathematical equalities or inequalities. The demand for quarters 1 and 2 (represented by i) and demand for quarters 3 and 4 (represented by j) have limits, where j≥i