J.R. S. answered 02/11/22
Ph.D. University Professor with 10+ years Tutoring Experience
Heat generated by combustion of 3.450 g naphthalene:
3.450 g x 40.1 kJ / g = 138 kJ
This heat will be absorbed by both the water and the calorimeter to raise the temperature of both.
q = mC∆T + Ccal∆T
q = heat = 138 kJ
m = mass of water = 1.000 kg
C = specific heat of water = 4.184 kJ/kgº
∆T = change in temperature = 4.345º
Ccal = calorimeter constant
Solve the equation for Ccal...
138 kJ = (1.000 kg)(4.184 kJ/kgº)(4.345º) + (Ccal)(4.345º)
138 kJ = 18.18 + 4.345Ccal
Ccal = 27.6 kJ/º