need help with this question

Question

need help with this chemistry question below how many grams of Agcl will be formed when 60 ml of .500m M agN03

is completely reacted to the balanced chemical reaction fecl3(aq)+3agno3-->3agcl+fe(no3)5(aq)

Answer 1

FeCl₃(aq) + 3AgNO₃ ==> 3AgCl(s) + Fe(NO₃)₃ ... balanced equation (note:your equation is wrong)

mols AgNO3 present = 60 ml x 1 L /1000 ml x 0.500 mol/L = 0.030 mols AgNO3

mols AgCl formed = 0.030 mols AgNO3 x 3 mols AgCl / 3 mol AgNO3= 0.030 mols AgCl formed

mass AgCl = 0.030 mols AgCl x 143 g /mol = 4.29 g