Hello! I am seeking assistance on this question. I need some help applying the distance time formula to this problem.

Question

A bungee jumper dives from a platform. The function ℎ = −16𝑡 2 + 200 gives her approximate height h in feet after t seconds. What will be the jumper’s height after 3 seconds?

Answer 1

To find the height after 3 seconds using the equation given, plug in the value given for t

h=-16(3)²+200

h=56 ft

Answer 2

h(t) = -16t^2 + 200

200 is the initial height = the height of the platform

minimum height is zero, when he touches the ground,

when 16t^2 = 200

t^2 = 200/16

t = (10/4)sqr2 = (5/2)sqr2

t = about 2.5(1.414) = 3.54 seconds

in 3 seconds h(3) = -16(3)^2 +200 = -16(9)+200

= 200-144= 56 feet from the ground

in about half a second more, he just touches the ground

actually using this distance formula would have the bungee jumper going even lower, into the ground, into a hole, hitting the ground or water at a velocity of h'(3) =-32(3) = 96 feet per second. the formula really doesn't describe how an actual bungee jump works. the bungee cord should slow down the descent with zero velocity at the bottom, but the formula has the opposite, with velocity increasing.

Answer 3

h=_16*(3)^2+200=56