The energy required to promote an electron in the H-atom from the third excited state to the 9th excited state as a function of K is a) -.053 KJ b) .099 KJ c) None.

Answer 1

Let me preface this by stating I am unfamiliar with the term "as a function of K" in this regard as I don't know what K is. So, I've given an approach based on what I understand about excitation of an electron in a hydrogen atom.

∆E = R_H (1/n_f² - 1/n_i²)

R_H = -2.179x10-18 J

nf = final energy level = 9

ni = initial energy level = 3

∆E = -2.179x10^-18 J (1/81 - 1/9)

∆E = -2.179x10^-18 J (-0.0988)

∆E = 2.15x10^-19 J = 2.15x10^-22 kJ