The first thing to realize is that the probability of a number being proportional means P(6) is 6 time more likely than P(1) and so on. Therefore takin P(1) as p, the sum of the probabilities = 1 = (1+2+3+4+5+6)p = 21p. So, the probabilities of the numbers appearing are 1/21, 2/21,...6/21)
In b, just compare p(6) to p(1)+p(2)