Lia W.

asked • 02/09/22

geometry help!!!

can someone please explain to me how to solve this



The perimeter of isosceles trapezoid is 160. If AB=x-2, BC=x-5, and CD=x, what is x?

1 Expert Answer

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Doug C. answered • 02/09/22

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Lia W.

would the expression happen to look like 3x-7=160?
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02/09/22

Doug C.

You are missing another x-5
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02/09/22

Lia W.

do i add the x-5 to the equation? like (3x-7+x-5=160) or do i add it in with the 3x-7?
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02/09/22

Doug C.

It works out the same either way, because 3x-7+x-5=4x-12. The initial equation could have looked like this: x + (x-2) + (x-5)+(x-5) = 160, but that simplifies to 4x-12 = 160. Take it from there.
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02/09/22

Lia W.

ohhh okay thank you i got 43
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02/09/22

Lia W.

can you help me with other problems on this same question or do i have to make a new question?
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02/09/22

Doug C.

Go ahead and ask one more. But try to explain what you have tried, or what you do not understand as part of posing the question.
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02/09/22

Lia W.

there's this one question that said: Given the rhombus ABCD. If the measure of \angle{BCA}=24\degree∠BCA=24°, then x=? and there's a picture that goes along with it but i cannot insert it on this website sadly. but mostly my problems when it comes to geometry is not knowing how to start the problem. especially when it only states one number in the problem.
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02/09/22

Doug C.

I assume x if the degree measure of another angle of the rhombus? In order to do these problems you have to understand the properties related to a rhombus, or other quadrilateral. For example, the four sides of a rhombus are equal. Its diagonals are perpendicular, opposite angles are congruent, consecutive angles are supplementary, and more.
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02/09/22

Doug C.

Just added a short video dealing with rhombus properties. Watch when you get a chance, pause and take notes.
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02/09/22

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