
Mark M. answered 02/08/22
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
A = 90° - 28 .2°
tan 28.2° = 306 / a
sin 28.2° = 306 / c
Ashtin W.
asked 02/08/22Mark M. answered 02/08/22
Mathematics Teacher - NCLB Highly Qualified
A = 90° - 28 .2°
tan 28.2° = 306 / a
sin 28.2° = 306 / c
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