
Yefim S. answered 02/07/22
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dy/cos2y = 2xdx; ∫sec2ydy = ∫2xdx; tany = x2 + C; tan0 = 32 + C; C = - 9.
So, tany = x2 - 9
Snow W.
asked 02/07/22(dy)/(dx)=2xcos^(2)y; y(3)=0
Yefim S. answered 02/07/22
Math Tutor with Experience
dy/cos2y = 2xdx; ∫sec2ydy = ∫2xdx; tany = x2 + C; tan0 = 32 + C; C = - 9.
So, tany = x2 - 9
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