x = blood pressure mean 119 SD 16
use standardized normal variable: z = (x - mean)/SD = (x - 119)/16
a) P(x > 160) = P(z > (160-119/16)) = P(z > 2.56) = P(z < -2.56) = 0.0052 = 0.52%
b) 2000 * 0.0052 = 10.4 ~ 10 people
c) P(140 < x < 160) = P((140-119/16) < z < (160-119/16)) = P(1.31 < z < 2.56) = P(z < 2.56) - P(z < 1.31) = 0.9948 - 0.9049 = 0.0899 = 8.99%
d) find z-score for 30th percentile (probability = 0.30) = -1.88
z = (x - mean)/SD
where x is value for 30th percentile
-1.88 = (x - 119)/16
16 * -1.88 + 119 = 88.92