A gas has a solubility in water of 14.8 g/L at 19°C and 607 kPa of pressure. What is its solubility in water at 14°C and 706 kPa of pressure?

Answer 1

C1/P1 = C2/P2 where C is concentration and P is pressure

C1 = 14.8 g/L

P1 = 607 kPa

C2 = ?

P2 = 706 kPa

Since solubility of a gas increases with increasing pressure, C2 should be greater than C1

14.8 g/L / 607 kPa = C2 / 706 kPa

C2 = 17.2 g/L