Chemistry 101 help

Question

A sample of solid iodine is heated with an electrical coil. If 19.2 calories of energy are added to a 12.4 gram sample and the final temperature is 38.8°C, what was the initial temperature of the iodine?

The specific heat of iodine is 0.102 cal/g

Answer 1

q = mC∆T

q = heat = 19.2 cal

m = mass = 12.4 g

C = specific heat = 0.102 cal/gº (note units of C has degrees in the units which were omitted in the question)

∆T = change in temperature = ?

Solve for ∆T ...

∆T = q / mC = 19.2 cal / (12.4 g)(0.102 cal/gº)

∆T = 15.2º

Since the final temperature is 38.8º the initial temperature would have been...

38.8º - 15.2º = 23.6ºC