J.R. S. answered 02/05/22
Ph.D. University Professor with 10+ years Tutoring Experience
Molar mass NaCl = 23.0 g + 35.5 g = 58.5 g / mol
Volume required = 100 cm3 x 1 dm3 /1000 cm3 = 0.1 dm3
moles = 0.500 mol / dm3 NaCl x 0.1 dm3 = 0.0500 moles NaCl required to make 100 cm3 of 0.500 mol / dm3
mass of NaCl = 0.0500 mols x 58.5 g / mol = 2.93 g NaCl needed (to 3 sig. figs.)