find an equation perpendicular to (2,1) and (1,6) containing the point (3,3)

Answer 1

Find the slope between the points (y₂-y₁)/(x₂-x₁)=m

The slope of the perpendicular is the negative reciprocal -1/m

Finally use the slope-point formula (y-3) = (-1/m)(x-3) to find the equation of the perpendicular line through (3,3)