Calculate the TOTAL number of electrons, protons and neutrons in 5.85g of NaCl.

Question

I am getting this as the answer-

Total no. of e- = 168.616 x 10^22

Total no. of p+ = 168.616 x 10^22

Total no. of n = 180.66 x 10^22

IS IT CORRECT?

Answer 1

First convert 5.85 NaCl to moles:

5.85 g NaCl x 1 mol / 58.4 g = 0.100 moles NaCl

0.100 mols NaCl produces 0.100 mols Na⁺ and 0.100 mols Cl^-

#electrons:

0.100 mol Na⁺ x 6.02x10²³ ions /mol x 10 electrons/ion = 6.02x10²³ electrons

0.100 mol Cl^- x 6.02x10²³ ions /mol x 18 electrons/ion = 10.8x10²³ electrons

Total electrons = 6.02x10²³ + 10.8x10²³ = 16.9x10²³ = 1.69x10²⁴ electrons (same answer as you got)

#protons:

0.100 mol Na⁺ x 6.02x10²³ ions/mol x 11 protons/ion = 6.62x10²³ protons

0.100 mol Cl^- x 6.02x10²³ ions/mol x 17 protons/ion = 10.2x10²³ protons

Total protons = 6.62x10²³ + 10.2x10²³ = 16.8x10²³ = 1.68x10²⁴ protons (same answer as you got)

#neutrons:

0.100 mol Na⁺ x 6.02x10²³ ions/mol x 12 neutrons/ion = 7.22x10²³ neutrons

0.100 mol Cl^- x 6.02x10²³ ions/mol x 18 neutrons/ion = 10.8x10²³ neutrons

Total neutrons = 7.22x10²³ + 10.8x10²³ = 18.0x10²³ = 1.80x10²⁴ neutrons (same answer as you got)