Chemistry concentration

Question

A solution of CuSO4 has a concentration of 1.342x10^-5M. Find the concentration of Cu^2+ in the solution in ppm. Assume density is 1.000 g/mL?

Answer 1

ppm is the same as mg / liter, so we'll just find the mg per liter.

CuSO₄ dissociates to produce Cu²⁺ + SO₄^2-

1.342x10^-5 M = 1.342x10^-5 moles / L

[Cu²⁺] = 1.342x10^-5 moles / L

Converting this to grams / L we have...

1.342x10^-5 mols / L x 63.55 g / mol = 8.528x10^-4 g / L

Converting this to mg / L (ppm), we have ...

8.528x10^-4 g / L x 1000 mg / g = 0.8528 mg/L = 0.8528 ppm