What is the correct set up for this problem?

Question

1 Fe₂O₃ (s) + 6 HCl (g) --> 2 FeCl₃ (s) + 3 H₂O (g)

How many grams of HCl are needed to react with 27.62 g of Fe₂O_3?

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= 37.29 g HCl

Answer 1

1 Fe₂O₃ (s) + 6 HCl (g) --> 2 FeCl₃ (s) + 3 H₂O (g)

The set up is to use dimensional analysis, as follows:

27.62 g Fe₂O₃ x 1 mol Fe₂O₃ / 159.7 g x 6 mol HCl / 1 mol Fe₂O₃ x 36.46 g HCl/mol = g HCl

Do the math to get the answer.