Use the following balanced equation to solve the problems below:

Question

1 Fe₂O₃ (s) + 6 HCl (g) --> 2 FeCl₃ (s) + 3 H₂O (g)

How many grams of FeCl₃ can be produced using 0.295 mol Fe₂O_3?

Answer 1

Fe₂O₃ (s) + 6 HCl (g) --==> 2 FeCl₃ (s) + 3 H₂O (g) ... balanced equation

Use dimensional analysis:

0.295 mol Fe₂O₃ x 2 mol FeCl₃ / 1 mol Fe₂O₃ x 162 g FeCl₃ / mol = 95.6 g FeCl₃