Hi Humar
Only DE and JK have numerical lengths assigned can you take it from there?
Brenda D.
tutor
You are welcome
Report
02/02/22
Humar P.
asked • 02/01/22pl help me to solve this
Which condition would prove ΔDEF ~ ΔJKL?
DF : JL = 1 : 32
DF : JL = 3/2 : 1
DE : JK = 1 : 3/2
EF : KL = 3/2 : 1
: 1
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Humar P.
GOT IT , ITS C. THANKS A LOT02/01/22