Calculate the amount of heat required to raise the temperature of a 99 g sample of water from 36° C to 69 ° C

Answer 1

Specific heat of water = 4.184 J/g/º

Use q = mC∆T

q = heat = ?

m = mass = 99 g

C = specific heat = 4.184 J/gº

∆T = change in temperature = 69º - 36º = 33º

q = (99 g)(4.184 J/gº)(33º)

q = 13,669 J = 13.7 kJ