
William W. answered 01/31/22
Math and science made easy - learn from a retired engineer
3) As you know, to get the mean (μ) of a set of samples, you add up the samples and divide by the number of samples:
In this case, we can replace one of the samples with 12 (let's say it is s3) and we can input μ = 8 and n = 9:
8 = (s1 + s2 + 12 + s4 + . . . s9)/9 and multiplying both sides by 9 we get:
72 = s1 + s2 + 12 + s4 + . . . s9 then subtraction 12 from both sides we get:
60 = s1 + s2 + s4 + . . . s9
To find the new mean, we take the sum of the samples (which is s1 + s2 + s4 + . . . sn or 60) and divide by the new number of samples n = 8
μnew = 60/8 = 7.5
4) If 12 = μ = (s1 + s2 + . . . sn)/n then 4•12 = 4(s1 + s2 + . . . sn)/n or 4•12 = (4s1 + 4s2 + . . . 4sn)/n meaning the new mean would be 4•12 or 48.
The other problems are similar to problem 3. Give them a try.