finding linear equations

Question

how do i find the linear equation with a slope of 1/3 and passes through the point (8, 2)

Answer 1

(y-2) = (1/3)(x-8)

y = x/3 - 8/3 + 2

y = x/3 -2/3 in slope intercept form

3y = x -2

x -3y = 2 in standard form

Answer 2

Start with the form of the linear equation Y = mX + b where m is the slope and b is the Y intercept.

As the slope is 1/3, we can write Y = 1/3 X + b. As the line passes through (8,2). we can substitute 8 for X and 2 for Y to get 2 = 1/3 x 8 + b. Now solve for b to get b = -2/3. The final equation is Y = 1/3 X - 2/3.

I must note that the point-slope method can be used as well. Y - 2 / X - 8 = 1/3. Solve for Y in terms of X.