if y=2(x+4) square -1 what is the axis symmetry

Answer 1

y = 2(x+4)^2 - 1

general form of the equation is

y = a(x-h)^2 + k where (h,k) is the vertex. Here h=-4 and k=-1

it's an upward opening parabola in vertex form with vertex = (-4, -1). The axis of symmetry runs vertically through the x coordinate of the vertex. axis of symmetry is x= -4

Answer 2

The standard form of a parabola is

y=a(x-h)²-k where the vertex is (h,k)

In this problem, the vertex is (-4,-1)

The axis of symmetry is the x coordinate of the vertex x = -4