Jonathan C.
asked • 01/27/22how do I solve for x
a right triangle that has 30 degrees for one angle, and 2x+42 degrees for another. And 5x+57 degrees on last angle.
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2 Answers By Expert Tutors
Denise G. answered • 01/27/22
Tutor
5.0
(547)
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
A triangle has a total angle measure of 180 degrees. So you can set up an equation.
angle 1 + angle 2 + angle 3 = 180 degrees Plug in what you have
30+(2x+42)+(5x+57) = 180 Combine like terms
7x+129=180 Subtract 129 from both sides
7x=51 Divide both sides by 7
x=7.2857
This seems like an odd answer. Is the problem entered correctly>?
Matt F. answered • 01/27/22
Tutor
5
(74)
Bachelor’s degree in Education with 20+ years experience teaching Math
The big question here is... what is the sum of all angles in ANY triangle. The answer is 180 degrees. That's the roadmap for this problem. Add up the angles and set them equal to 180.
30 + (2x+42) + (5x+57) = 180
30 + 2x + 42 + 5x + 57 = 180
2x+ 5x + 30 + 42 + 57 = 180
7x + 129 = 180
7x = 51
x = 7.2857...
Hope this helps!
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Jon S.
A right triangle with a 30 degree angle, is a 30-60-90 right triangle. The equations you have provided will not provide an x value which work for the "other" two angles: 60 and 90.01/29/22