J.R. S. answered 01/27/22
Ph.D. University Professor with 10+ years Tutoring Experience
We can't easily draw on this platform, so I'll do my best to give a written description of how to draw the Lewis structures.
A) BCl3: 24 valence electrons
Place B in the center with 3 Cl atoms singly bonded to the B. Place 3 lone pair sets of electrons (6 electrons) around each of the 3 Cl atoms. This uses all 24 valence electron. B does not have to have an octet.
B) N2O2: 22 valence electrons
Place the 2 N atoms in the center with an O on either end as follows:
O - N - N - O
Then place 3 lone pairs of electrons (6 electrons) around each O atoms and then place 1 lone pair of electrons (2 electrons) over each N atom. This uses all 22 valence electrons. But the 2 N atoms do NOT have an octet of electrons. To fix this, simply move 1 lone pair (2 electron) from each O atom to the adjacent N atom, and form a double bond between the N and O. It should look something like this...
O = N - N = O (with each O having 2 lone pairs of electrons)