Jade D. answered 01/24/22
Harvard A.B. in Chemistry and Physics, Interdisciplinary Experience
Hi Margie!
When we say "reaction order," we're referring to the value of the exponent on a reactant's concentration in the rate equation. In the same way that we say the "order" of a quadratic polynomial is 2, or a cubic polynomial is 3, because that is the value of their largest respective exponents, we say that the order of a reaction with respect to a reactant is the exponent that is applied to that reactant in the rate equation.
So what we have here is some equation like this:
rate = k[F]m[G]n
The order of the entire reaction would be m+n; however, we are being specifically asked for the reaction rate with respect to F (This tells us how quickly the rate of the equation increases as the concentration of F increases).
Since a 3-fold increase in the concentration of F yields a 9-fold increase in the rate, we can find that the exponent m necessary to allow this is 2, since 32=9.
So, if you doubled F instead of tripling it, you would have gotten a 4-fold increase. If you had quadrupled it instead of tripling it, you would have gotten a 16-fold increase!
I hope this helps! If you'd like more help in this vein, please take a look at my profile and contact me-- I'd be happy to tutor you!